Hi,
is it that the error term of an AR(1) process is an MA(1) process?
thanks in advance!
relationship between AR(1) and MA(1)
- meteor
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relationship between AR(1) and MA(1)
No, the error term from an AR(1) process is white noise.
The process you mesntioned is an ARMA(1,1).
The only relationship I can think of: AR(1)=Ma(infinity); MA(1)=AR(infitnity) (provided the process is invertible).
A good reference about time series : Brockwell and Davis
The process you mesntioned is an ARMA(1,1).
The only relationship I can think of: AR(1)=Ma(infinity); MA(1)=AR(infitnity) (provided the process is invertible).
A good reference about time series : Brockwell and Davis
malsain de corps et d'esprit
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panta_rhei
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relationship between AR(1) and MA(1)
hi, thanks for the reply.
but couldn't you rewrite the ar(1): Y_t=b*Y_t-1 + e_t into e_t=Y_t-b*Y_t-1 which is kind of a ma(1) ?
but couldn't you rewrite the ar(1): Y_t=b*Y_t-1 + e_t into e_t=Y_t-b*Y_t-1 which is kind of a ma(1) ?
- meteor
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relationship between AR(1) and MA(1)
I see your point but... the problem is that e_t is unobserved (and Y_t is)
So suppose that you want to estimate (the paramters of ) the second equation how do you gonna do? You will rewrite this equation into the first one.
So your first equation make more sense than the second one.
So suppose that you want to estimate (the paramters of ) the second equation how do you gonna do? You will rewrite this equation into the first one.
So your first equation make more sense than the second one.
malsain de corps et d'esprit
- functor
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relationship between AR(1) and MA(1)
Except for MA(1), the 'random shocks' are supposed to be uncorrelated, but Y_t and Y_{t-1} are correlated since they come from an AR(1). They are not even martingale differences, as E[ Y_t | Y_{t-1}, .. Y_1 ] is not zero.
Good people think in terms of categories and groups -- Confucius