I was looking through W****tt at the weekend and cam across this statement.
If we sell a delta neutral straddle at an implied vol, sigmai, and realized vol is sigma our expected p/l is
sqrt(2T/pi).(sigmai-sigma).S
(this makes sense)
and it's standard deviation is
sqrt(1-2/pi).sigma.S.sqrt(T)
This was just stated with no refs, proof or motivation. Where does this come from?
Standard deviation of a straddle p/l
- filthy
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Standard deviation of a straddle p/l
"Game's the same, just got more fierce"
- Baltazar
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Standard deviation of a straddle p/l
To me, it does not make sense, the PnL of a straddle hedging should depend on the hedging frequency.
Boucheau got something on that i believe (i don't have the book at hand)
Boucheau got something on that i believe (i don't have the book at hand)
Short Oil, Long Vinegar: Salad spread
- thefoolishfour
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Standard deviation of a straddle p/l
Which book is that??
Well, if being smart isn't gonna help me impress the chicks, then I want no part of it.
- Baltazar
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Standard deviation of a straddle p/l
I would say
Theory of Financial Risks: From Statistical Physics to Risk Management
but I am not sure.
Btw, maybe the guy meant unhedged
Theory of Financial Risks: From Statistical Physics to Risk Management
but I am not sure.
Btw, maybe the guy meant unhedged
Short Oil, Long Vinegar: Salad spread
- filthy
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Standard deviation of a straddle p/l
i assume he meant unhedged. the hedging induced p/l variance is just due to sampling error and was well covered by derman and kamal. this is different. could be a useful result but i have no idea where it comes from.
"Game's the same, just got more fierce"
- filthy
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Standard deviation of a straddle p/l
ok well how about this?
the derman kamal error for a straddle that is hedged once (at expiry) is sqrt(pi/4).vega.sigma
the ATM straddle is roughly 0.8. S.sigma.sqrt(T) so its vega is 0.8S. sqrt(T)
combining these we get an sd of 0.8.sqrt(pi/4).sigma.S.sqrt(T) which is close.
the derman kamal error for a straddle that is hedged once (at expiry) is sqrt(pi/4).vega.sigma
the ATM straddle is roughly 0.8. S.sigma.sqrt(T) so its vega is 0.8S. sqrt(T)
combining these we get an sd of 0.8.sqrt(pi/4).sigma.S.sqrt(T) which is close.
"Game's the same, just got more fierce"